[aklug] Re: need a way to communicate 10TB of storage

... and most of don't have a 1Mb/sec connection. Let's see ... Clearwire
= 256Mb/s, I only have about .5 TB total of data. Uhmmm ... About a 230
days, more or less? If I don't need my connection for anything else
(like work)!!

Where I work, I have the fastest upload speed I've personally ever seen,
30 Mb/s according to Mr Corliss' Speedtest.net site. There are also
something like 200 - 300 people sharing this connection. I hate to think
of what would happen to our bandwidth if a significant portion of those
people started using Carbonite, or similar.

I also suspect the company might shut off the connection after receiving
the bill for the overages :-)

Jim G

On Thu, 2011-03-31 at 15:37 -0800, Shane R. Spencer wrote:
> I've had to describe this as well to companies because of a disaster recovery product I'm
> building. I'm using time deltas to help people realize the incredible slowness their cloud
> based backup and restore solutions will achieve over the fast network they rely on so
> much. (Stupid lower 48 and their super high speed connection grubbing)
>
> Assuming 1 megabit full duplex and TCP all the way (just assume 20% flies out the window
> as a worst case scenario):
>
> (((1 * terabyte) / ((1 * megabit) / second)) / 0.8) = (x * day) = approx. x = 115.74074
>
> This doesn't fit into most peoples time budget for time it takes to get back important
> data. This is where off-site backups come in handy... however small businesses are
> storing a heck of a lot of information lately and would like an option other than bogging
> down their home DSL with nightly backups.. which is what I'm working on at the moment. To
> me it's faster to use the USPS than it is to restore this amount of information over the
> Internet. However many companies now have 10mb/s lines that average around 8mb/s on a
> stream.. lets see what Mr Math says.
>
> (((1 * terabyte) / ((8 * megabit) / second)) / 0.8) = (x * day) = approx. x = 14.467593
>
> Ok.. 14 days is a lot better than 115 days. Still not enough however.
>
> In order to beat the USPS you would need approximately 60mbit dedicated and fully
> available to your restore process for 1.92 days. For an overnight curiour (16 hours) you
> would need a 200mbit connection.
>
> Using UDP however and a transport layer I'm working on you can take that 20% packet waste
> and bump it down to around 1% for arguments sake and shave a few days off. It's
> impressive thinking about transfers in days.
>
> (((1 * terabyte) / ((1 * megabit) / second)) / 0.99) = (x * day) = approx. x = 93.527871
> (((1 * terabyte) / ((8 * megabit) / second)) / 0.99) = (x * day) = approx. x = 11.690984
> (((1 * terabyte) / ((60 * megabit) / second)) / 0.99) = (x * day) = approx. x = 1.5587979
> (((1 * terabyte) / ((200 * megabit) / second)) / 0.99) = (x * day) = approx. x = 0.46763936
>
>
> On 03/31/2011 12:26 PM, Jason McEachen wrote:
> > So a reporter asked me for a way to explain what 10TB of storage is.
> >
> > Got any cool "conversational analogies" for that amount of data?
> >
> > I found in various places:
> > 800,000 phone books
> > 16,000 music CDs
> > the library of congress (books)
> > 1400 movies (assume 700M)
> >
> > Thanks for any better illustrations,
> >
> > --Jason
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Received on Mon Apr 4 21:16:06 2011